here ~q OR ~s can be written as q->~s.
so equation becomes (p->q) ^ (r->s) ^ (q->~s)
(p->q) ^ (q->~s) = (p->~s) (transitive rule)
(p->~s) ^ (r->s) = (p->~s) ^ (~s->~r) (taking contrapositive)
= (p->~r) (transitive rule)
=(~p v ~r)
= ~p or ~r , HENCE PROVED.