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here ~q OR ~s can be written as q->~s.

so equation becomes (p->q) ^ (r->s) ^ (q->~s) 

(p->q) ^ (q->~s) = (p->~s) (transitive rule)

(p->~s) ^ (r->s) = (p->~s) ^ (~s->~r) (taking contrapositive)

                         = (p->~r) (transitive rule)

                         =(~p v ~r)

                        = ~p or ~r , HENCE PROVED.

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