0 0 votes The iteration formula to find the square root of a positive real number $b$ using the Newton Raphson method is $x_{k+1} = 3(x_k+b)/2x_k$ $x_{k+1} = (x_{k}^2+b)/2x_k$ $x_{k+1} = x_k-2x_k/\left(x^2_k+b\right)$ None of the above Numerical Methods gate1995 numerical-methods newton-raphson normal out-of-gatecse-syllabus + – Kathleen 3.4k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 3 3 votes Answer: B $x_{k+1} = x_k - \frac{f(x_k)}{f'(x)} = x_k - \frac{(x_k^2 - b)}{2x_k} = \frac{2x^2_k - x^2_k + b}{2x_k} = \frac{x^2_k + b}{2x_k}$ Rajarshi Sarkar answered Jun 2, 2015 Rajarshi Sarkar comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Answer is D. F(x)=x^2-b. Applying the general formula we can find the answer. kireeti answered Oct 26, 2014 kireeti comment Share Follow See 1 comment 1 1 comment reply akash.dinkar12 commented Nov 22, 2018 reply Follow flag No answer is only B... 0 0 replyShare Please log in or register to add a comment.
0 0 votes take x= root b x2=b f(x)=x2-b xn+1 = (x2+b) / 2x jayendra answered Dec 27, 2014 jayendra comment Share Follow 0 reply Please log in or register to add a comment.
