- $0 - C$ will be selected for $A = 0, B=0$.
- $1 - \bar C$ will be selected for $A = 0, B = 1.$
- $2 -\bar C$ will be selected for $A = 1, B = 0.$
- $3 -C$ will be selected for $A = 1, B = 1.$
So, $f = \bar A \bar B C + \bar A B \bar C +A \bar B \bar C + ABC$
$\qquad = \bar A (\bar BC + B \bar C) + A (\bar B \bar C + BC)$
$\qquad = \bar A (B \oplus C) + A (B \odot C)$
$\qquad = \bar A (B \oplus C) + A (\overline{B \oplus C})$
$\qquad = A \oplus B \oplus C$
Correct Answer: $C$