search
Log In
0 votes
136 views
.binary number  1.11111…………. are give find decimal number
in Digital Logic 136 views
0
1.96875
0

approximately = 2.00000 @Magma can u elaborate how u got the answer?

1
1 + 0.11111

$1+ (1 - 2^{-5} )$

 I didn't understand  on thing that  whether the 11111.......goes on  or only there's 5 1's ??
0
i think tha would goto infinty....
0
then it would be  2 :3
1
If it will go to infinity, then ans will be 2.

After decimal part will form an go series with common ratio = 1/2.

1/2 1/4 1/8... uptil infinity.. there sum will be 1
0
doesn't anyone think it is floating point number may represent with IEEE 754 format ?
0
@shaikh brother it's simple floating point to decimal conversion!
0
it simple G.P series of infinite terms

so common ratio=1/2 a=1

sum=2
0

@arvin

yes brother, everyone is thinking like that only, even i too... But after that i got that doubt,

yes my doubt is invalid !

due to how a floating number in Binary representation have dot in between ?

0

@Shaik Masthan yes I too thought for that for a moment but when I read that carefully it was simple

Please log in or register to answer this question.

Related questions

0 votes
1 answer
1
216 views
The following is a scheme for floating point number representation using 16 bits. Bit Position 15 14 .... 9 8 ...... 0 s e m Sign Exponent Mantissa Then the floating point number represented is: (−1)s(1+m×2−9)2e−31 , if the exponent ≠111111 0, otherwise What is the minimum difference between two successive real numbers representable in this system? Any help to solve this question is appreciated.
asked Jul 20, 2018 in Digital Logic iarnav 216 views
0 votes
0 answers
2
153 views
The difference between 201 and next larger double precision number is 2P , if IEEE double precision format is used then the value of P is ________. what is next larger precision number here ?
asked Feb 28, 2019 in Digital Logic syncronizing 153 views
0 votes
0 answers
3
1 vote
1 answer
4
...