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Q.1 In a country there are coins of denominations $2, $3, $5 and $7. How many different ways are there to pay exactly $10?

approach??

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Go on with highest denomination combination.

7  + 3 = 10

Break 7 int (5 + 2)

5 + 2 + 3 =10

Break 5 into (3+2)

3+2+3+2=10

No further breaking possible

So total 3 combination.

Edit after Subhanshu's comment

2 + 2 + 2 + 2 + 2 = 10

and

5 + 5 = 10

So 5 combinations.
edited by

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