0 0 votes $\sum_{k=0}^{\propto }\left ( \sum_{j=0}^{k}1 \right )x^{k} = \sum_{k=0}^{\propto}(k+1)x^{k}$ How LHS=RHS here? Mathematical Logic discrete-mathematics + – Reshu $ingh 714 views answer comment Share Follow Print See all 4 Comments 4 4 Comments reply Shaik Masthan commented Feb 8, 2019 reply Follow flag why you think those are not equal ? 1 1 replyShare Reshu $ingh commented Feb 8, 2019 reply Follow flag @Shaik Masthan Mmm Not able to get how (k+1) has come... 0 0 replyShare Shaik Masthan commented Feb 8, 2019 reply Follow flag left hand side if k=1, then j=0,j=1 two times 1 will be add ==> 1+1 right hand side, k=1, it will give 1+1 in general, left hand side, if k=i, then j=0,j=1,...j=i ==> total i+1 times 1 will be add right hand side, k=i, it will give i+1 3 3 replyShare Reshu $ingh commented Feb 8, 2019 reply Follow flag Thanks.Got it now @Shaik Masthan 0 0 replyShare Please log in or register to add a comment.
