TEST BOOK QUESTION

Question

        CAN SOMEBODY EXPLAIN THIS ANSWER PLZ !!!

Comments

don't post the answers until someone ask to provide...

Moreover try to type the text which can be typeable.

Answer 1

The given gates are XNOR gate.

At the first gate we can see that we have P XNOR 0, which gives 1 if p=0 and 0 if p=1 so we can say that our output from the first gate is P' (P complement).

Now this output is fed as a input to the next gate , so we have P ⊙ P' at the next gate. Now P ⊙ P' means the combination will always be either 0 ⊙ 1 or 1 ⊙ 0, so this gate will always give output as 0.

So, i/p to the 3rd gate is 0 ===> which is seen like original problem with 22-2 = 20 XNOR gates

So, after 2 more gates o/p again 0.

Finally, after 2 gates, after 4 gates, after 6 gates....... o/p is 0.

there are total 22 gates which are even ===> o/p at the end should be 0

Comments

thanks a lot sir

---

I am no sir..just an ordinary guy like u my friend and a gate 2020 aspirant.. :)