A Pizza Shop offers $6$ different toppings, and they do not take an order without any topping. I can afford to have one pizza with a maximum of $3$ toppings. In how many ways can I order my pizza?
Number of ways = No of pizza with 1 topping + No of pizza with 2 topping + No of pizza with 3 topping
= $ 6C1 + 6C2 + 6C3$
= $ 6+15+20= 41$
Option C) is correct
Answer: $\mathbf C$
$\because$ pizza cannot be ordered without any topping and pizza can be ordered with at most 3 toppings.
So, only $3$ possibilities are there $$= 6C_1 + 6C_2 + 6C_3$$
$$ = 6 + 15 + 20$$
$$ = 41$$
$\therefore \mathbf C$ is the correct option.