$[∀ x, α → (∃y, β → (∀ u, ∃v, y))] \equiv [∀ x, ¬α \vee (∃y, ¬β v (∀ u, ∃v, y))]$
Now, doing complement gives (complement of $∀$ is $∃$ and vice versa while propagating negation inwards as $∀x (P) \equiv ¬∃x (¬P)$ and $∃x (P) \equiv ¬∀x (¬P))$
$[∃ x, α \wedge (∀y, β \wedge (∃ u, ∀ v, ¬y))]$
(D) choice