4 4 votes Following Multiplexer circuit is equivalent to Sum equation of full adder Carry equation of full adder Borrow equation for full subtractor Difference equation of a full subtractor Digital Logic isro-2020 digital-logic combinational-circuit multiplexer normal + – Satbir 5.1k views answer comment Share Follow Print See 1 comment 1 1 comment reply Kiyoshi commented Apr 6, 2023 reply Follow flag (Full Adder) Sum $= \sum (1,2,4,7)$ and Carry $=\sum(3,5,6,7)$ (Full subtractor) Difference $= \sum(1,2,4,7)$ and Borrow $= \sum(1,2,3,7)$ Both A and D are correct. 5 5 replyShare Please log in or register to add a comment.
6 6 votes $Y= A'B'C + A'BC' + AB'C' + ABC$ $Y= A\ xor \ B \ xor \ C$ $Y= \sum(1,2,4,6,7)$, difference equation of full subtractor. Hence Option d) is correct Ashwani Kumar 2 answered Jan 13, 2020 Ashwani Kumar 2 comment Share Follow See all 3 Comments 3 3 Comments reply Swaraj Dasgupta commented Jan 13, 2020 reply Follow flag Ans can be A also... 4 4 replyShare rahul247 commented Feb 4, 2020 reply Follow flag There is a flaw in options , Both options (A) and (D) are correct. 0 0 replyShare Saransh Maurya commented Aug 30, 2024 reply Follow flag bro 6 kaha se aagaya 1 1 replyShare Please log in or register to add a comment.
2 2 votes The output Y of the given MUX is the equation for the difference of a full subtractor and Sum of a Full Adder. Y is the difference between A and B where C is the Barrow. Y is the Sum of A and B where C is the Carry_in. Y = B’A’C + B’AC’ + BA’C’ + BAC Y = (A ⊕ B ⊕ C) topper98 answered Mar 21, 2020 topper98 comment Share Follow 0 reply Please log in or register to add a comment.
