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Let us assume two of eigen values of S are  a ≠ 0 ,  b ≠ 0 with X and Y eigen vectors respectively.

YTX = x1y1   + x2y2 + x3y3

Since X is an eigen vector, therefore, 

SX = aX

YTSX = aYTX   (premultiplying YT on both sides)

(SY)TX = aYTX ( S is a real symmetric matrix)

bYTX = aYTX

(b-a)YTX = 0

YTX = 0   ( given that a != b)

 Eigen vectors X and Y are orthogonal to each other.

Therefore, Correct answer would be (d).

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