Let us assume two of eigen values of S are a ≠ 0 , b ≠ 0 with X and Y eigen vectors respectively.
YTX = x1y1 + x2y2 + x3y3
Since X is an eigen vector, therefore,
SX = aX
YTSX = aYTX (premultiplying YT on both sides)
(SY)TX = aYTX ( S is a real symmetric matrix)
bYTX = aYTX
(b-a)YTX = 0
YTX = 0 ( given that a != b)
Eigen vectors X and Y are orthogonal to each other.
Therefore, Correct answer would be (d).