1 1 vote why this qs has no effect of two level paging??i dont know if the answer given by madeeasy is right.. CO & Architecture virtual-memory co-and-architecture + – resuscitate 1.6k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes Page table entry is nothing but the frame number. So the number of frames possible is $2^{16}$. Frame size = 1024 Bytes Physical memory supported = number of frames * frame size = $2^{16}\ast 1024 = 2^{26}$ Bytes = 64 MB Sandeep Singh answered Jan 3, 2016 Sandeep Singh comment Share Follow See all 5 Comments 5 5 Comments reply Show 2 previous comments resuscitate commented Jan 3, 2016 i edited by resuscitate Jan 3, 2016 reply Follow flag arre i know that...without level paging,the problem is sitter...but it seems,they have given that for confusion only... 0 0 replyShare Amit Pal commented Dec 2, 2016 reply Follow flag @sandeep . Page table entry may contain other info as well like valid/invalid bit onfo + dirty bit +protection bit . you cannot write like page table entry = no of frames . 0 0 replyShare az7 commented Oct 29, 2019 reply Follow flag We can ignore those extra bits because in the question it is asking the maximum size of main memory supported. So the best-case scenario is that all 16 bits refer to the frame number. 0 0 replyShare Please log in or register to add a comment.
