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A fair die is tossed two times. the probability that 2nd toss results in value greater than first toss is ?

3 Answers

Best answer
11 11 votes
total outcomes = 36

expected outcomes={(1,2),(1,3),(1,4),(1,5),(1,6),(2,3),(2,4),(2,5),(2,6),(3,4),(3,5),(3,6),(4,5),(4,6),(5,6)}=15

hence Probability=15/36=5/12
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1 1 vote
Answer is {n(n-1)/2}/{n^2} = (n-1)/(2*n)

Here n = 6 so answer is 5/12.
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