0 votes 0 votes Compute each of these double sums. $\displaystyle{}\sum_{i=1}^{3}\sum_{j=1}^{2}(i-j)$ $\displaystyle{}\sum_{i=0}^{3}\sum_{j=0}^{2}(3i+2j)$ $\displaystyle{}\sum_{i=1}^{3}\sum_{j=0}^{2}j$ $\displaystyle{}\sum_{i=0}^{2}\sum_{j=0}^{3}i^{2}j^{3}$ Set Theory & Algebra kenneth-rosen discrete-mathematics set-theory&algebra descriptive + – admin asked Apr 21, 2020 admin 192 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.