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A bowl contains $10$ red balls and $10$ blue balls. A woman selects balls at random without looking at them.

  1. How many balls must she select to be sure of having at least three balls of the same color?
  2. How many balls must she select to be sure of having at least three blue balls?

1 Answer

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FOR A

Using Pigeonhole Principle we she must select X ball such that ceiling(X/2) =3 So X = 2*(3-1) +1 = 5 OR

2(red)+2(blue)+1 (either blue or red)=5

FOR B

 She has to select at least 13 balls to ensure the color.

10(red)+2(blue)+1(blue)=13

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