$p$, $q$, $r$ are simple statements and truth values are $T, F, T$ respectively.
Now, $((\neg p \vee q) \wedge r) \rightarrow p$
$((\neg p \vee q) \wedge r) \rightarrow p\equiv$ $((F \vee F) \wedge T) \rightarrow T\equiv$ $(F \wedge T) \rightarrow T\equiv$ $F \rightarrow T\equiv$ $T$
So, truth value of given expression: $((\neg p \vee q) \wedge r) \rightarrow p$ is TRUE.
Also, Option (C.) and (D.) are correct here.
In option (C.) if $r$ is false then given expression is TRUE.
$((\neg p \vee q) \wedge r) \rightarrow p \equiv$ $((F \vee F) \wedge F) \rightarrow T\equiv$ $(F \wedge F) \rightarrow T\equiv$ $F \rightarrow T\equiv$ $T$
In option (D.) if $q$ is true then given expression is TRUE.
$((\neg p \vee q) \wedge r) \rightarrow p \equiv$ $((F \vee T) \wedge T) \rightarrow T\equiv$ $(T \wedge T) \rightarrow T\equiv$ $T \rightarrow T\equiv$ $T$
Ans. is: A;C;D