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Detailed Video Solution: https://youtu.be/6aIuj2b2J38 

Since the denominator approaches $0$ as $x \rightarrow-2$, the necessary condition for this limit to exist is that the numerator approaches $0$ as $x \rightarrow-2$. Thus we solve $4 b-30+15+b=0$ to obtain $b=3. \displaystyle\lim _{x \rightarrow-2} \frac{3 x^2+15 x+18}{x^2+x-2}=-1$.

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