4 votes 4 votes Find the values of $A$ and $B$ that make $$ f(x)=\left\{\begin{array}{lll} x^2+1 & \text { if } & x \geq 0 \\ A \sin x+B \cos x & \text { if } & x<0 \end{array}\right. $$ differentiable at $x=0$. $A=0, B=1$ $A=1, B=0$ $A=0, B=-1$ $A=-1, B=0$ Calculus goclasses2025_csda_wq8 goclasses calculus continuity-and-differentiability 1-mark + – GO Classes asked May 24, 2023 • retagged Jun 12 by GO Classes GO Classes 109 views answer comment Share Follow See 1 comment See all 1 1 comment reply Deepak Poonia commented Sep 1, 2023 reply Follow Share Detailed Video Solution: https://youtu.be/6aIuj2b2J38 0 votes 0 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes f(x) is differentiable at x=0 → f(x) is continuous at x=0 So, $\lim_{x→0^{+}}$ f(x) = $\lim_{x→0^{-}}$ f(x) = f(0) => $\lim_{x→0^{-}}$ f(x) = f(0) => A sin(0) + B cos(0) = 0$^{2}$ + 1 => B = 1 KG answered May 27, 2023 • selected Sep 1, 2023 by Deepak Poonia KG comment Share Follow See all 0 reply Please log in or register to add a comment.