5 votes 5 votes The function $$ f(x)= \begin{cases}e^x & \text { if } \quad x \leq 1 \\ m x+b & \text { if } \quad x>1\end{cases} $$ is continuous and differentiable at $x=1$. Find the value of $m-b?$ $e$ $-e$ $\mathrm{e}-1$ $1-e$ Calculus goclasses2025_csda_wq8 goclasses calculus continuity-and-differentiability 1-mark + – GO Classes asked May 24, 2023 • retagged Jun 12 by GO Classes GO Classes 83 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
3 votes 3 votes Detailed Video Solution: https://youtu.be/6aIuj2b2J38 $m=e, b=0$. Solve $\displaystyle\lim _{x \rightarrow 1^{-}} e^x=\displaystyle{}\lim _{x \rightarrow 1^{+}}(m x+b)$ and $\displaystyle\lim _{x \rightarrow 1^{-}} \frac{e^x-e}{x-1}=\lim _{x \rightarrow 1^{+}} \frac{m x+b-(m+b)}{x-1}$ for $m$ and $b$. GO Classes answered May 24, 2023 • edited Sep 1, 2023 by Deepak Poonia GO Classes comment Share Follow See all 0 reply Please log in or register to add a comment.