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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 8

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In the circuit shown, $W$ and $Y$ are MSBs of the control inputs. The output $F$ is given by

  1. $F= W\overline{X}+\overline{W}X+\overline{Y}\overline{Z}$
  2. $F= W\overline{X}+\overline{W}X+\overline{Y}Z$
  3. $F= W\overline{X}\overline{Y}+\overline{W}X\overline{Y}$
  4. $F= ( \overline{W}+\overline{X}  )\overline{Y}\overline{Z}$
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