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Recent questions tagged goclasses2025_cs_wq19

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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 1
The logic function implemented by the circuit below is (ground implies a logic $\text{“0”})$\text{F=AND(P,Q})$\text{F=OR(P,Q})$\text{F=XNOR(P,Q})$\text{F=XOR(P,Q})$
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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 2
The figure below shows a multiplexer where $S_{1}$ and $S_{0}$ are the select lines, $I_{0}$ to $I_{3}$ are the input data lines, $\text{EN}$ is the enable line, ... {Q}R.$PQ+Q\overline{R}.$P\overline{Q}R+\overline{P}Q.$\overline{Q}+PR.$
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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 3
An $8$- to $1$ multiplexer is used to implement a logical function $Y$ as shown in the figure. The output $Y$ ... D$Y= \overline{A} \: \overline{B} \: D + A \: \overline{B} \: C$
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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 4
Consider the $ \text{2-bit}$ multiplexer $\text{(MUX)}$ shown in the figure. For $\text{OUTPUT}$ to be the $\text{XOR}$ of $\text{C}$ and $\text{D},$ ... , A_{3} = 0$A_{0} = 1, A_{1} = 1, A_{2} = 0, A_{3} = 0$
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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 5
In the circuit shown below, $\mathrm{P}$ and $\mathrm{Q}$ are the inputs. The logical function realized by the circuit shown below is$\mathrm{Y}=\mathrm{PQ}$\mathrm{ ... Y}=\overline{\mathrm{PQ}}$\mathrm{Y}=\overline{\mathrm{P}+\mathrm{Q}}$
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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 6
The Boolean function realized by the logic circuit shown is$\text{F} = \sum_{\text{m}} (0, 1, 3, 5, 9, 10, 14)$\text{F}=\sum_{\text{m}}(2,3,5,7,8,12,13)$\text{F}=\sum_{\text{m}}(1,2,4,5,11, 14,15)$\text{F}= \sum_{\text{m}}(2,3,5,7,8,9,12)$
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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 7
A four-variable Boolean function is realized using $4\times 1$ multiplexers as shown in the figure.The minimized expression for $\text{F(U,V,W,X)}$ ...
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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 8
In the circuit shown, $W$ and $Y$ are MSBs of the control inputs. The output $F$ is given by$F= W\overline{X}+\overline{W}X+\overline{Y}\overline{Z}$F= W\ ... {W}X\overline{Y}$F= ( \overline{W}+\overline{X} )\overline{Y}\overline{Z}$
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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 9
Consider the multiplexer based logic circuit shown in the figure.Which one of the following Boolean functions is realized by the circuit?$F= W \overline{S_1} \: \overline{S_2}$F= ... overline{W}+S_{1}+S_{2}$F= W\oplus S_{1}\oplus S_{2}$
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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 10
Consider the circuit shown in the figure. The Boolean expression $F$ implemented by the circuit is$\overline{X} \overline{Y} \overline{Z} + X Y +\overline{Y} Z $\overline ... $\overline{X} \overline{Y} \overline{Z} + XZ+ \overline{Y}Z $
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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 11
A Boolean function $f(A, B, C, D) = \prod (1,5,12,15)$ is to be implemented using an $8 \times 1$ multiplexer ($A$ is $MSB$). The inputs $ABC$ are connected to ... $\overline{D}, 0, \overline{D}, 0, 0, 0,D, \overline{D}$
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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 12
In the $4 \times 1$ multiplexer, the output $F$ is given by $F = A \oplus B$. Find the required input $'I_{3}, I_{2}, I_{1}, I_{0}'$.$1010$0110$1000$1110$
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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 13
Consider the following circuit which uses a $2$-to-$1$ multiplexer as shown in the figure below. The Boolean expression for output $F$ in terms of $A$ and $B$ is$A\oplus B$\overline{A+B}$A+B$\overline{A \oplus B}$
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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 14
The output $\text{F}$ of the digital circuit shown can be written in the form(s) __________$\overline{A \cdot B}$\overline{A} + \overline{B}$\overline{A+B}$\overline{A} \cdot \overline{B}$
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GO Classes CS 2025 | Weekly Quiz 19 | Multiplexer | Question: 15
A $4 \times 1$ multiplexer with two selector lines is used to realize a Boolean function $\text{F}$ having four Boolean variables $\text{X, Y, Z}$ and $\text{W}$ as shown below. ...
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