3 votes 3 votes The logic function implemented by the circuit below is (ground implies a logic $\text{“0”})$ $\text{F=AND(P,Q})$ $\text{F=OR(P,Q})$ $\text{F=XNOR(P,Q})$ $\text{F=XOR(P,Q})$ Digital Logic goclasses2025_cs_wq19 goclasses digital-logic combinational-circuit multiplexer 1-mark + – GO Classes asked Oct 12, 2023 • retagged Jun 5 by GO Classes GO Classes 148 views answer comment Share Follow See 1 comment See all 1 1 comment reply Deepak Poonia commented Oct 22, 2023 i edited by Deepak Poonia Oct 22, 2023 reply Follow Share Question Source: https://ec.gateoverflow.in/1800/gate-ece-2011-question-7 Detailed Video Solution of this Question: https://youtu.be/AtqUACtsI2Y Video Solution of Entire Quiz 31: https://youtu.be/iH-tWF51Zbc 0 votes 0 votes Please log in or register to add a comment.
Best answer 6 votes 6 votes The input is connected with ground i.e “0”. So, $I_{0} = \bar{\bar{0}}= 0$ $I_{1 }= I_{2} = \bar{0} = 1$ $I_{3} = 0$ So, $F= P’Q’.(0) + P’Q.(1) + PQ’.(1) + PQ.(0) = P’Q + PQ’ = XOR \ (P, Q) $ $Ans: Option \ D$ AniMan_7 answered Oct 12, 2023 • selected Oct 22, 2023 by Deepak Poonia AniMan_7 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Detailed Video Solution: https://youtu.be/AtqUACtsI2Y $I_0 = 0, I_1 = 1, I_2 = 1, I_3 = 0$ So, $F = \overline{P} \bar{Q}(0) + \overline{P} Q(1) + P \overline{Q} (1) + PQ (0) $ $F = \overline{P} Q + P \overline{Q} = XOR(P,Q)$ Deepak Poonia answered Oct 22, 2023 Deepak Poonia comment Share Follow See all 0 reply Please log in or register to add a comment.
