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Let $f : X \rightarrow Y$ and $g : Y \rightarrow Z$ be functions. We can define the composition of $f$ and $g$ to be the function $g \circ f : X \rightarrow Z$ for which the image of each $x \in X$ is $g( f (x))$. That is, plug $x$ into $f$, then plug the result into $g$ (just like composition in algebra and calculus).


(a) If $f$ and $g$ are both injective, must $g \circ f$ be injective? Explain.
(b) If $f$ and $g$ are both surjective, must $g \circ f$ be surjective? Explain.
(c) Suppose $g \circ f$ is injective. What, if anything, can you say about $f$ and $g$? Explain.
(d) Suppose $g \circ f$ is surjective. What, if anything, can you say about $f$ and $g$? Explain.

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Detailed Video Solution: https://youtu.be/1qOTs03imLU 

Composition of Injective Functions is Injective. 

Composition of Surjective Functions is Surjective. 

Composition of Bijective Functions is Bijective. 

If $f \circ g$ is bijective, then $g$ is one to one and $f$ is onto.

All these statements, with PROOF: Function Composition Important Questions - with Proof (Click HERE)

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