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How many programmable fuses are required in a PLA which takes $16$ inputs and gives $8$ outputs? It has to use $8$ OR gates and $32$ AND gates.

1. $1032$
2. $776$
3. $1284$
4. $1536$
| 3.4k views
0

Mine is coming 1280...
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@Kapil

But can please explain how you got 1280.
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Related concept.

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diagram of PLA

Total programmable fuses= fuses required by AND gates + fuses required by OR gates

(Fuses are attached to and- or gate inputs to allow inputs to reach the and - or gates and If fuses don't work , then no input can reach to these gates of PLA)

Fuses required by AND gates = 2* no. Of inputs * no. Of and gates = 2*16*32= 1024 fuses

Fuses required by OR gates = no. Of outputs * no. Of and gates  = 8* 32 = 256 ( total outputs should be equal to no. Of OR gates and inputs have to cross AND gates and then goto OR gates)

Total fuses = 1024+ 256= 1280

by Veteran (50.9k points)
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+1
from where u got these formulas?
+1

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But option C is 1284
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That is wrong. Right answer is 1280 only.