5 5 votes How many programmable fuses are required in a PLA which takes $16$ inputs and gives $8$ outputs? It has to use $8$ OR gates and $32$ AND gates. $1032$ $776$ $1284$ $1536$ Digital Logic isro2013 digital-logic pla + – Misbah Ghaya 9.4k views answer comment Share Follow Print See all 5 Comments 5 5 Comments reply Show 2 previous comments Aishwarya Gujrathi commented Apr 9, 2018 reply Follow flag Refer: https://gateoverflow.in/167512/isro-2017-ece-digital-logic Related concept. 0 0 replyShare Gurdeep Saini commented Mar 2, 2019 reply Follow flag diagram of PLA now read the answer 2 2 replyShare amitarp818 commented Oct 1, 2023 reply Follow flag is this in gate syllabus?? 0 0 replyShare Please log in or register to add a comment.
Best answer 16 16 votes answer is C) Total programmable fuses= fuses required by AND gates + fuses required by OR gates (Fuses are attached to and- or gate inputs to allow inputs to reach the and - or gates and If fuses don't work , then no input can reach to these gates of PLA) Fuses required by AND gates = 2* no. Of inputs * no. Of and gates = 2*16*32= 1024 fuses Fuses required by OR gates = no. Of outputs * no. Of and gates = 8* 32 = 256 ( total outputs should be equal to no. Of OR gates and inputs have to cross AND gates and then goto OR gates) Total fuses = 1024+ 256= 1280 Kapil answered Jun 19, 2016 • selected Mar 13, 2017 by Kapil Kapil comment Share Follow See all 5 Comments 5 5 Comments reply Show 2 previous comments anchitjindal07 commented Nov 15, 2018 reply Follow flag But option C is 1284 0 0 replyShare ShrutiS commented Oct 9, 2019 reply Follow flag That is wrong. Right answer is 1280 only. 0 0 replyShare Pratyush Priyam Kuan commented Sep 27, 2020 reply Follow flag @ Kapil shouldn’t the answer be 1288 . Should we not consider the fuses due to not gates. shouldn’t we add 8 to 1280.? 0 0 replyShare Please log in or register to add a comment.
