6 6 votes If the frame to be transmitted is $1101011011$ and the CRC polynomial to be used for generating checksum is $x^{4}+x+1$, than what is the transmitted frame? $11010110111011$ $11010110111101$ $11010110111110$ $11010110111001$ Computer Networks isro2013 computer-networks crc-polynomial + – Misbah Ghaya 8.6k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 4 4 votes frames transmitted 1101011011 generator g(x)= X^4+X+1x4 x4+x+1x4+x+1 ORDER OF GENERATOR 4.THEN APPEND FOUR 0'S TO THE LOWER END OF THE FRAME CRC polynomial 10011 Answer is 11010110111110 srestha answered Apr 27, 2016 • selected Jun 30, 2016 by asu srestha comment Share Follow See all 4 Comments 4 4 Comments reply Rajsree commented Jun 28, 2016 reply Follow flag Sir, Can you please explain why are we adding four zeros at the end? 0 0 replyShare asu commented Jun 30, 2016 reply Follow flag @arjun sir this ans is correct but not addded in exam 1 1 replyShare Manoja Rajalakshmi A commented Dec 11, 2017 reply Follow flag Computation:(padding with zeroes) https://en.wikipedia.org/wiki/Cyclic_redundancy_check 0 0 replyShare Siddharth_Perkar commented Jul 25 reply Follow flag Simple Rule for adding no. of zero's :If the generator polynomial (divisor) has n bits, then append: n-1 bits 0 0 replyShare Please log in or register to add a comment.