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All inhabitants of the Old Forest are either Ents or Bents. Ents always tell the truth and Bents always lie. During a visit to the Old Forest, you encounter four inhabitants $-\mathrm{A}, \mathrm{B}, \mathrm{C}$ and D . They make the following assertions.

A: Exactly one of us is a Bent.
B: Exactly two of us are Bents.
C: Exactly three of us are Bents.
D: Exactly four of us are Bents.
 

How many of them are Bents?

  1. $1$
  2. $2$
  3. $3$
  4. $4$

     

3 Answers

1 1 vote

Since all the statements are (pairwise) mutually contradictory, at most one of them is an Ent. If there are no Ents, then D would be telling the truth, making him an Ent. But that is a contradiction. So there is exactly one Ent, and consequently three Bents. So C, as the only truth-teller, is an Ent, and the others are Bents.

Explanation-

To solve this problem, let's analyze the statements made by each inhabitant one by one and figure out how many of them are Bents.

Restating the inhabitants' statements:

  • A: Exactly one of us is a Bent.
  • B: Exactly two of us are Bents.
  • C: Exactly three of us are Bents.
  • D: Exactly four of us are Bents.

Ents always tell the truth, and Bents always lie. Therefore, if an inhabitant is an Ent, their statement must be true. If they are a Bent, their statement must be false.

Let's analyze each statement in the case of different numbers of Bents:

Case 1: Assume that there is 1 Bent.

  • A's statement: "Exactly one of us is a Bent."
    • Since there is 1 Bent, A's statement is true. A must be an Ent.
  • B's statement: "Exactly two of us are Bents."
    • This is false because there is only 1 Bent, so B must be a Bent.
  • C's statement: "Exactly three of us are Bents."
    • This is false because there is only 1 Bent, so C must be a Bent.
  • D's statement: "Exactly four of us are Bents."
    • This is false because there is only 1 Bent, so D must be a Bent.

In this case, A is the only Ent, and B, C, and D are all Bents. This configuration is consistent with the conditions, and it results in 3 Bents.

Case 2: Assume that there are 2 Bents.

  • A's statement: "Exactly one of us is a Bent."
    • This is false, so A must be a Bent.
  • B's statement: "Exactly two of us are Bents."
    • This is true, so B must be an Ent.
  • C's statement: "Exactly three of us are Bents."
    • This is false, so C must be a Bent.
  • D's statement: "Exactly four of us are Bents."
    • This is false, so D must be a Bent.

In this case, A, C, and D are Bents, and B is an Ent. This configuration results in 3 Bents, which is consistent with the assumption of 2 Bents. However, this doesn't work because we assumed there were 2 Bents to begin with, and the result shows 3.

Case 3: Assume that there are 3 Bents.

  • A's statement: "Exactly one of us is a Bent."
    • This is false, so A must be a Bent.
  • B's statement: "Exactly two of us are Bents."
    • This is false, so B must be a Bent.
  • C's statement: "Exactly three of us are Bents."
    • This is true, so C must be an Ent.
  • D's statement: "Exactly four of us are Bents."
    • This is false, so D must be a Bent.

In this case, A, B, and D are Bents, and C is an Ent. This configuration results in 3 Bents, which is consistent with the assumption of 3 Bents.

Case 4: Assume that there are 4 Bents.

  • A's statement: "Exactly one of us is a Bent."
    • This is false, so A must be a Bent.
  • B's statement: "Exactly two of us are Bents."
    • This is false, so B must be a Bent.
  • C's statement: "Exactly three of us are Bents."
    • This is false, so C must be a Bent.
  • D's statement: "Exactly four of us are Bents."
    • This is true, so D must be an Ent.

However, this case results in 3 Bents rather than 4. So, this case doesn't work.

Conclusion:

The only consistent solution is that there are 3 Bents (A, B, and D are Bents, while C is the Ent).

so, option (C) is correct

0 0 votes

Detailed Video Explanation with Multiple Ways to Solve: https://youtu.be/tW5xu99n7AU?t=4426&feature=shared

Answer: C

Since all the statements are (pairwise) mutually contradictory, at most one of them is an Ent.

If there are no Ents, then D would be telling the truth, making him an Ent. But that is a contradiction.

So there is exactly one Ent, and consequently three Bents. So C, as the only truth-teller, is an Ent, and the others are Bents.


Only 2 things to understand in this question:

1. Among all the 4 statements, any two of them can NEVER be true. So, at most one of them is true statement i.e. at most one of them is an Ent.

2. If $D$ is an Ent, then $D$ speaks truth, so, $D$ becomes a Bent which is contradiction. So, $D$ is a Bent & statement made by $D$ is false, so, at least one of them is an Ent.

From $1,2;$ we know that $1$ of them is an Ent, & $3$ of them are Bents, which makes $C$ an Ent as he spoke the truth.

Detailed Video Explanation with Multiple Ways to Solve: https://youtu.be/tW5xu99n7AU?t=4426&feature=shared

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