2 2 votes A graph is $d$ - regular if every vertex has degree $d$. For a $d$ - regular graph on $n$ vertices, which of the following must be TRUE?$d$ divides $n$At least one of $d$ and $n$ is evenBoth $d$ and $n$ are oddAt least one of $d$ and $n$ is odd Graph Theory goclasses discrete-mathematics graph-theory goclasses-cs-dpp goclasses-cs-dpp-day-54 goclasses-graph-theory-practice-questions goclasses-dm-practice-questions + – GO Classes 488 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
2 2 votes B. reason : Total degree = 2. |E| n.d = 2.|E|. at least one of d and n has to be even because R.H.S is even. shashank sharma_1 answered Jul 23, 2025 shashank sharma_1 comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes We know that the sum of degrees is twice the number of edges. Now, sum of degrees is $n d$, as there are $n$ vertices of degree $d$ each. As $n d$ is even, either one of them should be definitely even. GO Classes answered Jul 23, 2025 • reshown Jul 25, 2025 by GO Classes Support GO Classes comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes n vertices d degrees e edges Then, nd = 2e n or d must be Even, Option B is the Correct soudipta_dutta answered Jul 23, 2025 soudipta_dutta comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes B JAY_THAKAR answered Jan 12 JAY_THAKAR comment Share Follow 0 reply Please log in or register to add a comment.