3 3 votes The minimum number of edges in a connected graph with ${ }^{\prime} n^{\prime}$ vertices is equal to$n(n-1)$ $\frac{n(n-1)}{2}$ $n^2$ $n-1$ Graph Theory goclasses discrete-mathematics graph-theory goclasses-cs-dpp goclasses-cs-dpp-day-54 goclasses-graph-theory-practice-questions goclasses-dm-practice-questions + – GO Classes 596 views answer comment Share Follow Print See 1 comment 1 1 comment reply shashank sharma_1 commented Jul 23, 2025 reply Follow flag D 1 1 replyShare Please log in or register to add a comment.
0 0 votes The minimum number of edges for undirected connected graph is ( $\mathbf{n - 1}$ ) edges.For the maximum number of edges (assuming simple graphs), every vertex is connected to all other vertices which gives arise for $n(n-1) / 2$ edges (use handshaking lemma). Detailed Video Explanation GO Classes answered Jul 23, 2025 • reshown Jul 25, 2025 by GO Classes Support GO Classes comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes A tree with n vertices always has exactly n−1 edges. soudipta_dutta answered Jul 23, 2025 soudipta_dutta comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes D JAY_THAKAR answered Jan 12 JAY_THAKAR comment Share Follow 0 reply Please log in or register to add a comment.