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(p ∧ ¬q) ∨ (¬p ∧ q) ∨ (¬p ∧ ¬q)

Case:1 p = TRUE => (T ∧ ¬q) ∨ (F ∧ q) ∨ (F ∧ ¬q) = ¬q ∨ F ∨ F = ¬q

a. ¬p ∨ ¬q = F ∨ ¬q = ¬q

b. p ∨ ¬q = T ∨ ¬q = T

c. p ∨ q = T ∨ q = T

d. ¬p ∨ q = F ∨ q = q

Case:2 p = FALSE => (F ∧ ¬q) ∨ (T ∧ q) ∨ (T ∧ ¬q) = F ∨ q ∨ ¬q = TRUE

a. ¬p ∨ ¬q = T ∨ ¬q = TRUE

b. p ∨ ¬q = F ∨ ¬q = ¬q

c. p ∨ q = F ∨ q = q

d. ¬p ∨ q = T ∨ q = TRUE

 

Answer: A

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