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GO Classes DPP | GATE CS | Discrete Mathematics| Propositional Logic

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2 Answers

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Case:1 A = TRUE => ¬ [((T ∧ (B ∨ C)) → (T ∨ B)) → T] = ¬ [((B ∨ C) → T) → T] = ¬(T → T) = ¬T = False

a. B ∨ ¬C

b. ¬A = ¬T = False

c. ¬C 

Case:2 A = FALSE => ¬ [((F ∧ (B ∨ C)) → (F ∨ B)) → F] = ¬ [(F → B) → F] = ¬(T → F) = ¬F = True

a. B ∨ ¬C

b. ¬A = ¬F = True

c. ¬C 

 

Answer: B

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