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Let $S=\{1,2,3, \ldots, 100\}$. The number of non-empty subsets $A$ of $S$ such that the product of elements in $A$ is even, is

  1. $2^{50}\left(2^{50}-1\right)$
  2. $2^{50}-1$
  3. $2^{50}+1$
  4. $2^{100}-1$

4 Answers

0 0 votes
Total no of even subset = 2^n

In this,there is a case when set empty so we have subtract that case

2^n-1

Total no of odd subset=2^n

There is no need of subtract as set cannot be empty

Hence answer will (2^n-1)*2^n
0 0 votes
Total 2^100-1

odd product possible hoga jab sab odd elements ek set me add honge 50 odd elements are there
50C1 +50C2 .... 50C50 = 2^50-1 undesirable .

Desirable = Total - undesirable.

2^100 - 1 -(2^50- 1) = 2^100 - 2^50

so option A is correct.
 
0 0 votes

Option A is correct 

A product of integers is even if and only if at least one of the integers in the set is even.

Conversely, a product is odd only if every single number in the set is odd.

 Breaking Down the Set $S$

The set $S = \{1, 2, 3, \dots, 100\}$ contains:

  • 50 Even numbers: $\{2, 4, 6, \dots, 100\}$

  • 50 Odd numbers: $\{1, 3, 5, \dots, 99\}$

 Method 1: Subtraction (Total - Undesirable)

  1. Total non-empty subsets of $S$:

    Since there are 100 elements, the total number of subsets is $2^{100}$. Excluding the empty set,

    $$\text{Total} = 2^{100} - 1$$

  2. Subsets with an ODD product:

    To get an odd product, we must pick elements only from the 50 odd numbers.

    The number of non-empty subsets using only odd numbers is:

    $$\text{Odd Products} = 2^{50} - 1$$

  3. Subsets with an EVEN product:

    $$\text{Even Products} = (2^{100} - 1) - (2^{50} - 1)$$

    $$\text{Even Products} = 2^{100} - 1 - 2^{50} + 1 = 2^{100} - 2^{50}$$

     

Method 2: Direct Construction

  • Pick the even numbers: To ensure the product is even, we must pick at least one even number from the 50 available.

    Number of ways = $2^{50} - 1$ (Total even subsets minus the empty even set).

  • Pick the odd numbers: We can pick any combination of the 50 odd numbers (including none at all), because the presence of an even number already guarantees an even product.

    Number of ways = $2^{50}$.

            Even product: $(2^{50} - 1) \times 2^{50}$


Why the answer is NOT $2^{50} \times 2^{50}$ is not Correct 

The value $2^{50} \times 2^{50}$ is equal to $2^{100}$.It includes the Empty Set: $2^{100}$ includes the case where you pick zero even numbers and zero odd numbers. The question specifically asks for non-empty subsets.

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