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UGC NET CSE | December 2012 | Part 3 | Question: 21

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It can be reduced as 11 similar balls into 3 different boxes...

x>=1 , x2>=2,  x3>=3

So 11 -(1+2+3) = 5 (remaining balls)

It is combination with repetition...

With 5 similar items and 3 different items...

So ans is (5+3-1)C5

That is 7C5
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