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connect First 4 Lamps(L1 , L2 , L3 , L4) to extension 1 and take power from Extension 2 . In Extension 2 we can connect only 3 lamps because out of 4 one port is busy to supply power to extension 1.

Similarly, For other extensions we can connect only 3 lamps because one port is busy to supply power to other extension.

Connect Last Extension (Ex 19) to Electric outlet.

We can connect 4 Lamps to first extension

Number of Extension required for Remaining 54 lamps = $\frac{54}{3}$=18 Extension

Total Extension required to connect all 58 Lamps = 18+ 1 =19

Hence,Option(D)19 is the correct choice.

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All extensions can allow 3 lamps and one plug for next extension. 

Thus,         3)58(19

                     57

                 ---------

                      1

So we have got solution for 57 lamps, but one lamp still needs to be connected. But, this time in the last 19th board, we have one outlet also left..

So, 19 extension boards will be enough.

Answer:

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