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A computer employs RAM chips of 256 $\times$ 8 and ROM chips of 1024 $\times$ 8. The computer system needs 2K bytes of RAM, 4K bytes of ROM and four interface units, each with four registers. A memory-mapped I/O configuration is used. The two highest-order bits of the address bus are assigned 00 for RAM, 01 for ROM and 10 for interface registers.

  1. How many RAM and ROM chips are needed?
  2. Draw a memory-address map for the system.
  3. Give the address ranges in hex for RAM, ROM and interface.
  4. Show the interconnection of CPU and the chips.

1 Answer

1 1 vote

Answer to parts (i), (ii) and (iii) are here:

https://www.scribd.com/doc/23675579/Sheet-5

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