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The number of divisors of $2100$ is ____.

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Best answer
54 54 votes
Answer: 36

$2100 = 7\times 3\times 2^2 \times 5^2$

Hence, total number of factors will be $= (1+1)\times (1+1)\times (2+1)\times (2+1) \\= 2 \times 2\times 3 \times 3 \\= 36$,

because any factor is obtained by multiplying the prime factors zero or more times. (one extra for zero)
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$2100 = 7 * 3 * 2^{2} * 5^{2}$

To calculate the total number of divisors, take each power in the prime factorization obtained, and:

Step 1: Increment the power.

$(1+1) (1+1) (2+1) (2+1)$

Step 2: Calculate the product of it:

$(1+1) * (1+1) * (2+1)* (2+1)$

Answer: 36

1 1 vote

Ans  - 36

Detailed Explanation to get clear understanding

Start with 2100:

  • 2100 ÷ 2 = 1050

  • 1050 ÷ 2 = 525 → So 2²

  • 525 ÷ 3 = 175 → So 3¹

  • 175 ÷ 5 = 35

  • 35 ÷ 5 = 7 → So 5²

  • 7 is a prime → 7¹


Final Prime Factorization of 2100:

2100 = 2² × 3 × 5² × 7

Using the divisor formula:
d(n) = (a₁ + 1) × (a₂ + 1) × ... × (aₖ + 1)

d(2100) = (2+1)(1+1)(2+1)(1+1)=3⋅2⋅3⋅2=36 divisors

0 0 votes
Prime factors for 2100 is 2²X5²X3X7

 

So, we got that possibilities for factors like

 

For 2 it 2⁰, 2¹ or 2² so there are 3 choices for it

 

For 5 it is 5⁰, 5¹ or 5² so there are 3 choices for it

 

For 3 it is 3⁰ or 3¹ so there are 2 choices for it

 

For 7 it is 7⁰ or 7¹ so there are 2 choices for it

 

Hence multiplying as it is independent events

 

2*2*3*3=36
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