52 52 votes Consider the following $2 \times 2$ matrix $A$ where two elements are unknown and are marked by $a$ and $b$. The eigenvalues of this matrix are $-1$ and $7.$ What are the values of $a$ and $b$? $\qquad A = \begin{pmatrix}1 & 4\\ b&a \end{pmatrix}$ $a = 6, b = 4$ $a = 4, b = 6$ $a = 3, b = 5$ $a = 5, b = 3 $ Linear Algebra gatecse-2015-set1 linear-algebra eigen-value easy + – Misbah Ghaya 12.2k views answer comment Share Follow Print See all 3 Comments 3 3 Comments reply JashanArora commented Jan 23, 2020 reply Follow flag Trace of any square matrix = sum of eigenvalues. $1+a=-1+7$ => $a=5$ 2 2 replyShare Hira Thakur commented Jan 24, 2024 reply Follow flag Similar question: GATE CSE 2010 | Question: 29 2 2 replyShare chetan-naik commented Oct 17, 2024 reply Follow flag For anyone who forgot the beautiful properties of trace and determinant, Solving $\left|A-\lambda I\right|$ leads to $(1-\lambda)(a-\lambda)-4b=0$ Put $\lambda = 7,-1$ and solve the two linear equations using Gaussian elimination ;) P.S. Remember the properties. They are very useful. And don't solve 2 linear equations in 2 variables using GE. 2 2 replyShare Please log in or register to add a comment.
Best answer 74 74 votes $\text{Sum of Eigenvalues} = \text{trace of matrix (sum of diagonal elements) } $$\implies -1 + 7 = 1+a$ $\implies a=5$$\text{Product of Eigenvalues} = \text{Determinant of matrix}$$\implies -1 \times 7 = a - 4b$ $\implies b=3$This gives $a = 5$ and $b = 3$Answer : $D$ amarVashishth answered Oct 11, 2015 • edited Dec 24, 2025 by Umesh Shelke amarVashishth comment Share Follow 0 reply Please log in or register to add a comment.
11 11 votes As, we know - product of eigenvalues of a matrix is equal to determinant of that matrix. so, (-1) × 7 = det(A) =(1 × a ) - (4 × b) so, a - 4b = -7 -------(1) also, trace (sum of the diagonal elements) of a matrix is equal to sum of eigenvalues of the matrix. so, 1 + a = -1+7 =6 so, a = 5 -------(2) from equation (1) and (2) b = 3 So,answer is D Priya_das answered Feb 13, 2015 Priya_das comment Share Follow 0 reply Please log in or register to add a comment.
6 6 votes sum of eigen values=> trace of the matrix determinent =>product of eigen values a+1=6=>a=5 a-4b=-7 5-4b=-7 12=4b b=3.. so a=5 and b=3 Joker answered Mar 6, 2016 Joker comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Multiplication of Eigen values = Determinant of matrix -1 * 7 = -7 -7 = a – 4b now go through options option D fits perfectly so a = 5 b = 3 ProtonicRED answered Jan 17, 2022 ProtonicRED comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Sum of eigen values = Trace of the matrix -1+7 = 1+a 6 = 1 + a a= 5 ------------------------------------------------------------------------ product of eigen values = determinent of the matrix -1 x 7 = a-4b -7 = a-4b -7 = 5-4b 4b = 5+7 4b = 12 b= 3 hope my answer helps u a lot akshay_123 answered Sep 6, 2023 akshay_123 comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes D is the answer Prashant-G answered Mar 28 Prashant-G comment Share Follow 0 reply Please log in or register to add a comment.