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Recent posts tagged gatecse-preparation-schedule

False : Consider $E: \{1,2,3,4\}$, $F:\{3,4,5,6\}$ $f(E) = \{5,6,7,8\}$ $f(F)=\{7,8,11,6\}$ $f(E \cap F) = \{7,8\}$ where as, $f(E) \cap f(F) = \{6,7,8\}$ Becomes TRUE only when $f$ ... $ f(E \cap F) \subseteq f(E) \cap f(F)$ $\subseteq$ becomes $=$ only when $f$ is one-one - when the mappings are unique for each element.
posted May 10 in From GO Admins gatecse 3,925 views
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