search
Log In

Recent posts tagged gatecse-2022

3
False : Consider $E: \{1,2,3,4\}$, $F:\{3,4,5,6\}$ $f(E) = \{5,6,7,8\}$ $f(F)=\{7,8,11,6\}$ $f(E \cap F) = \{7,8\}$ where as, $f(E) \cap f(F) = \{6,7,8\}$ Becomes TRUE only when $f$ ... $ f(E \cap F) \subseteq f(E) \cap f(F)$ $\subseteq$ becomes $=$ only when $f$ is one-one - when the mappings are unique for each element.
posted May 10 in From GO Admins gatecse 3,925 views
To see more, click for the full list of questions or popular tags.
...