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Answer is (C) Poisson Probability Density Function (with mean $\lambda$) =$\dfrac{ \lambda^{k}} { \left(e^{\lambda}k!\right)}$, We have to sum the probability density function for $k = 0,1$ and $2$ and $\lambda = 3$(thus finding the cumulative mass function) =$\left(\dfrac{1}{e^{3}}\right) + \left(\dfrac{3}{e^{3}}\right) + \left(\dfrac{9}{2e^{3}}\right)$ =$\dfrac{17}{\left(2e^{3}\right)}$
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