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Let $G$ be a simple graph with $20$ vertices and $100$ edges. The size of the minimum vertex cover of G is $8$. Then, the size of the maximum independent set of $G$ is:

  1. $12$
  2. $8$
  3. less than $8$
  4. more than $12$

6 Answers

Best answer
89 89 votes

Vertex cover: A set  of vertices such that each edge of the graph is incident to at least one vertex of the set.

Therefore, removing all the vertices of the vertex cover from the graph results in an isolated graph and the same set of nodes would be the independent set in the original graph.

Size of minimum vertex cover $= 8$
Size of maximum independent set $= 20 - 8  =12$

Therefore, correct answer would be (A).

Reference :- http://mathworld.wolfram.com/MaximumIndependentVertexSet.html

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6 6 votes

Answer: (A)

Explanation: Background Explanation:
Vertex cover is a set S of vertices of a graph such that each edge of the graph is incident to at least one vertex of S.
 

Independent set of a graph is a set of vertices such that none of the vertices in this set have an edge connecting them i.e. no two are adjacent. A single vertex is an independent set, but we are interested in maximum independent set, that is largest set which is independent set.

Relation between Independent Set and Vertex Cover : An interesting fact is, the number of vertices of a graph is equal to its minimum vertex cover number plus the size of a maximum independent set. How? removing all vertices of minimum vertex cover leads to maximum independent set.

So if S is the size of minimum vertex cover of G(V,E) then the size
of maximum independent set of G is |V| – S.

Solution:
size of minimum vertex cover = 8
size of maximum independent set = 20 – 8 =12
Therefore, correct answer is (A).

 

Reference : https://www.geeksforgeeks.org/gate-gate-cs-2005-question-11/

2 2 votes

Statement: Minimum vertex cover number(𝜷) + Size of maximum Independent set(𝛼) = Size of vertex set (n)

 

Proof: 

Statement 1:  

A graph G(V,E) if S ⊆ V is a Vertex Cover then (V - S) is Independent Set.

 

Proof 1:

In the picture only green coloured edges are possible.

Now we can see that all the vertices in the set (V - S) can’t be adjacent. Hence (V - S) is an Independent Set.      (Proved)

 

Statement 2:

A graph G(V,E) if S ⊆ V is a Independent Set then (V - S) is Vertex Cover  

 

Proof 2:

 

Again in the picture below only green coloured edges can be present and if red coloured edges are present then S can’t be an Independent Set because the vertices will be adjacent.

 

So where are all the adjacent edges ?

They must be in between S and (V - S) or in (V - S). So we can see (V - S) covers all the edges hence it is a Vertex Cover.         (Proved)

                 

 

Statement 3:   𝛼 + 𝜷 = n

 

Proof 3:

Size of any Verte Cover ≥ Size of minimum Vertex Cover(𝜷)

Size of any Independent Set ≤ Size of maximum Independent Set(𝛼)

 

 

From figure 1, 𝛼  ≥ |V - S|  ⇒ 𝛼  ≥ n  - 𝜷 ⇒ n ≤  𝛼 + 𝜷 …………..(i)

From figure 2, 𝜷   ≤ |V - S| ⇒ 𝜷 ≤ n - 𝛼 ⇒ n ≥  𝛼 + 𝜷 .....................(ii)


From (i) and (ii),  n = 𝛼 + 𝜷   (Proved)
 

So here 𝛼 = 20 - 8 = 12

Credit: Deepak Poonia (Teacher of GO Classes)

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0 0 votes
Let's understand this .

Vertex cover - Set of all the vertices that cover all the  edges.

Independence set - Set of all vertices that are not connected with each other by any of the edge.

Now we can say ,

Total vertices - Number of independent vertices+ Number of vertices that have connection with some other ( in other words it's not independent vertices)

Now think what does vertex cover indicate. Its just set of vertices that cover all the edges hence they will be definately not independent.

Hence 20 = independent vertices+ 8

Hence independent vertices set =12
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