14,929 views
29 29 votes

Consider the following system of linear equations : $$2x_1 - x_2 + 3x_3 = 1$$ $$3x_1 + 2x_2 + 5x_3 = 2$$ $$-x_1+4x_2+x_3 = 3$$ The system of equations has

  1. no solution
  2. a unique solution
  3. more than one but a finite number of solutions
  4. an infinite number of solutions

6 Answers

Best answer
37 37 votes
rank of matrix $=$ rank of augmented matrix $=$ no of unknown $=$ $3$
so unique solution..

Correct Answer: $B$
• edited by
17 17 votes

Determinant of matrix =14 which is non zero

If The determinant of the coefficient matrix is non zero then definitely the system of given equation has a unique solution 

 so option B

5 5 votes
                                                       (B) A unique solution .

 

5 5 votes

Method-1:

2

 

3

 

-1

-1

 

2

 

5

3

 

5

 

1





 

In this matrix we can clearly see that three columns are Linearly independent and 3 L.I columns in R3 space

 

So It will fill the space and Ax=b 

 

So there will be unique solution

 

If the column space is filled and Ax=0 then there will be a trivial solution

Method-2: Converting into  echelon form

After converting into echelon form we obtain augmented matrix as

2

 

0

 

0

-1

 

7

 

0

3

 

1

 

32

1

 

1

 

46

We can clear see all the columns have pivot and there is no [00..00|b] form

 

So there will be unique solution

Method-3: By using rank

rank[A] =3 and rank[A|b]=3  and number of columns =3

Therefore unique solution is possible

Answer is option-B

 

2 2 votes
determinant of matrix is 14 which is not zero which means that the vectors of the matrix are LI , unique solution
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