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+1 vote
Maximum no of edges in a triangle-free, simple planar graph with 10 vertices
in Graph Theory by Active (3.1k points) | 218 views

2 Answers

+1 vote

Minimum degree in any triangle free graph

$\delta =4$

by using Euler's formula

e-n+(k+1) =r   {k=#f connected components}


=> e-8=r

As, min degree of region is 4

$4r\leq 2e$

=> 4(e-8) $\leq$ 2e

=> 4e-32  $\leq$ 2e

=> e $\leq$16

by Loyal (7.8k points)
for a triangle-free graph, can't have any vertex with degree 1 or 2??
0 votes

For a triangle free graph, every face has degree $\ge$ 4. Therefore $2e \le 4f \implies f \ge \frac{e}{2}$ (This is because $\sum deg(f_i) = 2e $). We know from Euler's formulae that $n-e+f=2$. So, $f=2+e-n \implies \frac{e}{2} \ge 2+e-n \implies 2(n-2) \ge e$. Here $n=10$. Therefore, $e\le 16$.

by Loyal (5.4k points)

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