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29 votes

Answer: (b)
Explanation: In slotted ALOHA we divide the time into slots and force the station to send only at the beginning of the time slot. Here slot time is 50 ms, so number of slots in 1 second = 1/(50 X 10^-3) => 20 slots/sec

  • Requests per second = 70
  • Time slots per second = 20
  • Channel load = No. of Requests / No. of Slots = 70 / 20 = 3.5

Reference: http://www.cs.wichita.edu/~chang/lecture/cs742/homework/hwk3-sol.txt

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5 votes

Answer is (B) part.

70 request per second so number of request in one time slot(50 ms) will be (70*50)/1000 = 3.5 (which is channel load means request per time slot)

2 votes
2 votes
70 request/sec

time is slotted in units of 50 msec

channel load = 50 msec * 70 request / sec

                    = 3.5

b option
Answer:

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