4 votes 4 votes How to find the number of solutions value of (n,p) to satisfy (5*n + 9*p) = 23 Combinatory generating-functions + – hem chandra joshi asked Jan 16, 2018 hem chandra joshi 486 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes coffiencient of $ x^{23} $ in $(1-x^{5})^{-1} * (1-x^{9})^{-1}$ = $_{2}^{1}\textrm{C} * _{3}^{2}\textrm{C}$ = 2*3 = 6 Neeraj Chandrakar answered Jan 17, 2018 Neeraj Chandrakar comment Share Follow See all 3 Comments See all 3 3 Comments reply hem chandra joshi commented Jan 17, 2018 reply Follow Share what are they btw? 0 votes 0 votes Prateek kumar commented Jan 28, 2018 reply Follow Share (1+x^5+(x^5)^2 +(x^5)^3 +......)*(1+x^9+(x^9)^2+........) -----> x^23 (Need from them) only give one term = x^5 * (x^9)^2 so "only one solutions" i am getting 2 votes 2 votes Aakash Roy commented Feb 17, 2018 reply Follow Share can you please explain in detail step by step ? 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes (5*n + 9*p) = 23 u can solve it like this... (x1+x2=23) here x1<=(0,5,10,15,20) as n=0 1 2 3 x2 <=(0,9,18).... the coeficient of x23 hs_yadav answered Jan 28, 2018 hs_yadav comment Share Follow See all 0 reply Please log in or register to add a comment.
