0 votes 0 votes My explanation I have provided, Please rectify the mistake where I am going wrong :) HeadShot asked Jul 13, 2018 HeadShot 831 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply HeadShot commented Jul 13, 2018 reply Follow Share Please correct me where I am going wrong , Thank you :) 0 votes 0 votes srestha commented Jul 13, 2018 reply Follow Share Ans 27? 0 votes 0 votes HeadShot commented Jul 13, 2018 i edited by HeadShot Jul 13, 2018 reply Follow Share @ srestha They have provided ans as option ( D) Will you explain the approach please. 0 votes 0 votes Shaik Masthan commented Jul 13, 2018 reply Follow Share i hope this images helps 1 votes 1 votes Please log in or register to add a comment.
Best answer 2 votes 2 votes Option d is right abhishekmehta4u answered Jul 13, 2018 • selected Jul 13, 2018 by HeadShot abhishekmehta4u comment Share Follow See all 17 Comments See all 17 17 Comments reply Show 14 previous comments gauravkc commented Jul 14, 2018 reply Follow Share But if the set has numbers from 1 to n (Say) For a relation to be reflexive, all (x,x) for x=1..n should be in relation. Any one of them missing in relation will make it irreflexive. However, in asymmetric, there should be no (x,x) relation. So I guess we cannot say that. Please correct me if I'm wrong. 0 votes 0 votes srestha commented Jul 14, 2018 reply Follow Share but definition of irreflexive is No $\left ( x,x \right )$ element will be present there Any $\left ( x,x \right )$ is present then it is not irreflexive and nor even reflxive right? 0 votes 0 votes gauravkc commented Jul 14, 2018 reply Follow Share Oops, my mistake. Sets who contain at least all (x,x) pairs are reflexive Sets who do not contain any (x,x) pair are irreflexive Sets who have few (x,x) pairs are neither reflexive nor irreflexive 0 votes 0 votes Please log in or register to add a comment.