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Na462 size in bits?

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 Mk Utkarsh

Size of next address field in a control word = 30-(15+4) = 11 bits, So Size of control memory = 2048, we can fit 2048 control instructions in control memory

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size will we be 2^11*(30)
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2 Answers

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SIZE OF THE CONTROL MEMORY WILL BE 8 KB BECAUSE WE HAD GOT 2^11 NEXT ADDRESS FIELD AND THEN WE WANT TO MULTIPLY WITH CONTROL WORD IN BYTE SO THE ANS WILL BE 8 KB

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your answer as well explanation both are wrong

because there is no need to convert 30 bit into 4 byte 

this is not a page table entry that we have to take it in the size of byte 

if you dont understood watch this https://gateoverflow.in/181814/control-memory

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Width of control word (micro operations+condition+next address) is 30 bits

Given, micro.op :15 bits ; 16 status conditions so condition: 4 bits.... From this next address field is 30-(15+5) = 11bits

Size of control memory: 2^11 addresses * 30 bits size

Answer is 7680B or 7.5KB

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