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SIZE OF THE CONTROL MEMORY WILL BE 8 KB BECAUSE WE HAD GOT 2^11 NEXT ADDRESS FIELD AND THEN WE WANT TO MULTIPLY WITH CONTROL WORD IN BYTE SO THE ANS WILL BE 8 KB
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Width of control word (micro operations+condition+next address) is 30 bits

Given, micro.op :15 bits ; 16 status conditions so condition: 4 bits.... From this next address field is 30-(15+5) = 11bits

Size of control memory: 2^11 addresses * 30 bits size

Answer is 7680B or 7.5KB

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