1 votes 1 votes Gate Fever asked Oct 31, 2018 Gate Fever 347 views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply Show 3 previous comments Gate Fever commented Oct 31, 2018 reply Follow Share answer is 8 what approach did u use ?? i was doing like numbers div by 2 = 4*3*2=24 numbers div by 3= 4* 3 *1=12 but i was not able to find the numbers which will be divisible by both 2 and 3 and hence divisible by 6 0 votes 0 votes Soumya Tiwari commented Oct 31, 2018 reply Follow Share The no should be divisible by both 2 and 3 to be divisible by 6 so for this Last digit of the no should be either 2 or 4 Lets first take last digit be 2 then the other 2 digit should sum to either 4 or 7 Why? Because sum of all 3 should be divisible by 3 so for this possible value are for 4-(1,3) can't take (2,2) as repetition not allowed so possible 3 digit no are-132 or 312 similarly for 7 (4,3) and 2 permutation 432 and 342. Similarly take 4 in unit place and the other two digit sum can be 5(2,3) or 8(5,3) So total 8 2 votes 2 votes Gate Fever commented Oct 31, 2018 reply Follow Share thanks! 0 votes 0 votes Please log in or register to add a comment.