Co Interrupt

Question

Consider a single-level cache with an access time of 2.5 ns with a block size of 64 bytes. Main memory uses a block transfer capability that has a first word (4 bytes) access time of 50 ns and an access time of 5 ns for each word thereafter. If hit ratio of cache memory is 95%, then average memory access time is __________. [Upto 3 decimal places]

I'm getting 8.750. But the answer given is 8.875.

My approach is

0.95*2.5+0.05(2.5+50+15*5).

Answer explain

2.5+0.05(2.5+50+15*5)

which is correct?

I find made easy accurate with answers for all subjects except Co.

Comments

I am also getting the same answer as you and the same way!

Answer 1

you  are using simulatenous access and made easy used heirarchical access.that’s why there is difference in the answer