603 views

1 Answer

Best answer
2 2 votes
A relation if reflexive iff ,

xRx exists . Which is true here since x= x^1 for all x $\in$ Z.Thus it is reflexive.

It is not symmetric , since (2,4) exists but (4,2) does not belong to the Relation .

It is anti-symmetric , because of the reflexive elements.

If xRy exists then y=x^i and if yRz exists then z=y^j . so we can write z = (x^i)^j.

 

Thus the relation is reflexive , anti-symmetric and transitive . Thus a Poset.
selected by
Position:
Show:

Related questions

0 0 votes
1 answers 1 answer
314
314 views
hrupam asked Apr 16, 2025
314 views
Let A be a set with |A| = n, and let R be an equivalence relation on set A with |R| = r. Which of the following is/are TURE?(A) r – n will always be even.(B) r – n will a...
1 1 vote
1 1 answer
1.2k
1.2k views
Sona Barman asked Mar 8, 2019
1,216 views
How to check a relation is transitive or not from its matrix representation? Please help me with an example.
0 0 votes
1 1 answer
1.2k
1.2k views
srestha asked Mar 7, 2019
1,172 views
Let $A=\left \{ 1,2,3 \right \}$. Number of relation on $A$ which are neither reflexive, nor irreflexive but symmetric is ___________Ans given 48but I got 8Please verify
0 0 votes
1 answers 1 answer
1.0k
1.0k views
Abhipsa asked Jan 23, 2019
1,029 views
What is the number of relations S over set {0,1,2,3} such that (x,y) $\epsilon$ S $\Rightarrow x = y$ ? Thanks.