The Gateway to Computer Science Excellence
0 votes
12 views

Let $\cos ^6 \theta = a_6 \cos 6 \theta  + a_5 \cos 5 \theta + a_4 \cos 4 \theta + a_3 \cos 3 \theta + a_2 \cos 2 \theta + a_1 \cos  \theta +a_0$. Then $a_0$ is

  1. $0$
  2. $1/32$
  3. $15/32$
  4. $10/32$
in Numerical Ability by Veteran (425k points)
recategorized by | 12 views
0

Question not edited properly. There is a mistake.

Please log in or register to answer this question.

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true
50,645 questions
56,598 answers
195,838 comments
102,143 users