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Let $\cos ^6 \theta = a_6 \cos 6 \theta + a_5 \cos 5 \theta + a_4 \cos 4 \theta + a_3 \cos 3 \theta + a_2 \cos 2 \theta + a_1 \cos \theta +a_0$. Then $a_0$ is

1. $0$
2. $1/32$
3. $15/32$
4. $10/32$

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Question not edited properly. There is a mistake.