ISI2015-MMA-27

Question

Let $\cos ^6 \theta = a_6 \cos 6 \theta  + a_5 \cos 5 \theta + a_4 \cos 4 \theta + a_3 \cos 3 \theta + a_2 \cos 2 \theta + a_1 \cos  \theta +a_0$. Then $a_0$ is

• A. $0$
• B. $1/32$
• C. $15/32$
• D. $10/32$

Comments

Naveen Kumar 3

Question not edited properly. There is a mistake.